Python Program to Check Leap year

In this program, you will learn to check whether a year is a leap year or not. We will use nested if... else to solve this problem.

#Python program to check if the input year is a leap year or not 

year = 2000

# To get year (integer input ) from the user 
# year = int(input("Enter s year:"))

if (year % 4) == 0:
     if(year % 100) == 0:
            if(year % 400) == 0:
                     print("{0} is a leap year" .format (year))
           else:
                    print("{0} is not a leap year" .format (year))
     else:
          print("{0} is a leap year" .format (year))
else:
    print("{0} is not a leap year" .format (year))


Output

2000 is a leap year